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-0.021x^2+1.5x+1.75=0
a = -0.021; b = 1.5; c = +1.75;
Δ = b2-4ac
Δ = 1.52-4·(-0.021)·1.75
Δ = 2.397
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{2.397}}{2*-0.021}=\frac{-1.5-\sqrt{2.397}}{-0.042} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{2.397}}{2*-0.021}=\frac{-1.5+\sqrt{2.397}}{-0.042} $
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